In the structure CH_3 - C^2H(C^1H_3) - C^3H_2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Homolytic bond dissociation energy $(BDE)$ is inversely proportional to the stability of the free radical formed after the bond breaks. Stability

Vedclass · Accepted Answer

$C_1-H > C_4-H > C_3-H > C_2-H$

Vedclass · Answer

(D) Homolytic bond dissociation energy $(BDE)$ is inversely proportional to the stability of the free radical formed after the bond breaks. Stability of free radicals follows the order: $3^\circ > 2^\circ > 1^\circ$. In the given molecule (isopentane): $1.$ $C_2-H$ is a $3^\circ$ bond (forms a $3^\circ$ radical,which is the most stable). $2.$ $C_3-H$ is a $2^\circ$ bond (forms a $2^\circ$ radical). $3.$ $C_1-H$ and $C_4-H$ are $1^\circ$ bonds (form $1^\circ$ radicals,which are the least stable). Among the $1^\circ$ bonds,the $C_4$ radical is slightly more stable than the $C_1$ radical because $C_4$ has two $\beta$-hydrogens available for hyperconjugation,while $C_1$ has only one. Therefore,the $BDE$ order is: $C_1-H > C_4-H > C_3-H > C_2-H$.

In the structure $CH_3 - C^2H(C^1H_3) - C^3H_2 - C^4H_3$,the order of homolytic bond dissociation energy for $C_1-H, C_2-H, C_3-H$ and $C_4-H$ is:

Similar Questions

The reactions of alkanes are explosive with which halogen?

Which is the smallest alkane that exhibits isomerism?

How do you account for the formation of ethane during the chlorination of methane?

Total number of isomeric compounds (including stereoisomers) formed by monochlorination of $2$-methylbutane is................

Give the combustion reaction of alkane.

Vedclass Test Series

Exam Paper Generator

Online Exam Module